Question

Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:

7 9 11 10
10 11 9 7
#include

int main(void) {
const int NUM_VALS = 4;
int courseGrades[NUM_VALS];
int i;

for (i = 0; i < NUM_VALS; ++i) {
scanf("%d", &(courseGrades[i]));
}

/* Your solution goes here */

return 0;
}

Answer 1

Answer:

The solution code is written in C

1. #include <stdio.h>
3. int main()
4. {
5.    const int NUM_VALS = 4;
6.    int courseGrades[NUM_VALS];
7.    int i;
8.    
9.    for (i = 0; i < NUM_VALS; ++i) {
10.        scanf("%d", &(courseGrades[i]));
11.    }
12.    
13.    /* Your solution goes here */
14.    for(i = 0; i < NUM_VALS; ++i){
15.        printf("%d ", courseGrades[i]);
16.    }
17.    printf("\n");
18.    
19.    for(i = NUM_VALS - 1; i >=0; --i){
20.        printf("%d ", courseGrades[i]);
21.    }  
22.    printf("\n");
23.    
24.    return 0;
25. }

Explanation:

The solution is highlighted in the bold font.

To print the elements forward, create a for loop to start the iteration with i = 0 (Line 14). This will enable the program to get the first element and print if out followed with a space (Line 15). The program will take the second element in the next iteration.

To print the elements backward, create a for loop to start the iteration with i = NUM_VALS - 1. The NUM_VALS - 1 will give the last index of the array and therefore the loop will start printing the last element, followed the second last and so on (Line 19 - 21).