Answer:
38.7°
Explanation:
The force on a current carrying wire is given as
F = (B)(I)(L) sin θ
where
B = magnetic field = 80 mT = 0.08 T
I = current in the wire = 40 A
(F/L) = 2.0 N/m
θ = angle between the magnetic field and the direction of current flow (basically angle between the wire and the magnetic field) = ?
(F/L) = (B) (I) sin θ
2 = 0.08 × 40 × sin θ
sin θ = (2/3.2) = 0.625
θ = sin⁻¹ (0.625)
θ = 38.7°
Hope this Helps!!!
Answer:
38.68 °C
Explanation:
Using,
F = BILsinФ....................... Equation 1
F/L = BIsinФ...................... Equation 2
Where F/L = force per unit length, B = Magnetic Field, I = current, Ф = angle between the wire and the magnetic Field
make Ф the subject of the equation
Ф = sin⁻¹[(F/L)/BI]................... Equation 3
Given: F/L = 2 N/m, B = 80 mT = 0.08 T, I = 40 A.
Substitute into equation 3
Ф = sin⁻¹(2/(0.08×40))
Ф = sin⁻¹(0.625)
Ф = 38.68 °C
Hence the angle between the wire and the magnetic Field = 38.68 °C
