Question

Question 2 of 5
Marcos has a square sprocket ABCDgraphed in the coordinate plane. The square sprocket was rotated 180° about the origin to form
A'B'C'D'. The vertices are A'(-6, -3), B'(-2, -3), C (-2,1), and D'(-6,1). What are the coordinates of A?​

Answer 1

The coordinates of the point A is (6,3)

Explanation:

Given that the Marcos has a square sprout ABCD graphed in the coordinate plane.

The square sprocket was rotated 180° about the origin to form  A'B'C'D'.

The vertices are A'(-6, -3), B'(-2, -3), C (-2,1), and D'(-6,1).

We need to determine the coordinates of the point A.

Since, the rotation was 180° about the origin, the coordinate rule is given by

$(x,y)\implies(-x,-y)$

Using the above rule, let us translate the coordinate (-6, -3)

Substituting the value x = -6 and y = -3 in the coordinate rule, we get,

$(-6,-3)\implies(-(-6),-(-3))$

Simplifying, we get,

$(-6,-3)\implies(6,3)$

Thus, the coordinates of the point A is (6,3)