Answer:
The period of oscillation will be larger on the moon than on earth.
Explanation:
For small oscillations the period [tex]T[/tex] of the pendulum is given by the equation
[tex](1). \:T = 2\pi \sqrt{\dfrac{L}{g} }[/tex]
where [tex]L[/tex] is the length of the pendulum, and [tex]g[/tex] is the acceleration due to gravity.
Now, acceleration to due to gravity is less on the moon ([tex]g =1.625m/s^2[/tex]) than on the earth [tex](g = 9.8m/s^2)[/tex], this means a smaller value of [tex]g[/tex] in equation (1) means [tex]\dfrac{L}{g}[/tex] will be bigger, and therefore, [tex]T[/tex] will be larger on the moon than on earth.
