Respuesta :
Answer:
a) 1,970,500 cars per year
b) [tex]f(x)=1970.5x+10,002[/tex] (in thousands)
c) 23,795,500 cars
Step-by-step explanation:
2009 ----- 10,002 cars
2013 ------ 17,884 cars
a)
The average rate of change in basically the slope of the line. We would need 2 points to find slope. THe slope is change in y points divided by change in x points.
Let 2009 be the initial year, so x = 0 at this point and each successive year is x = 1, x= 2, etc.
So, first point would be:
(0, 10002)
Second point therefore:
(4, 17884) [2013 is 4 years from 2009]
Now, lets find the Slope:
Slope = (17884 - 10002) / (4 - 0) = 1970.5 thousands per year = 1,970,500 per year
b)
Now, we have to find the equation of the line given the 2 points.
This is given by:
[tex]y-y_1=m(x-x_1)[/tex]
Where m is the slope found and x_1 would be first x point, which is 0 and y_1 would be first y point, which is 10002
SO,
[tex]y-10,002=1970.5(x-0)\\y-10,002=1970.5x\\y=1970.5x+10,002[/tex]
We change "y" to "f(x)" in the notation according to problem. Thus, the equation is:
[tex]f(x)=1970.5x+10,002[/tex] (in thousands)
c)
We have to predict the number of cars sold on 2016, which is 7 years from base year 2009. So,
x = 7
We will number of cars, that is f(x).
So we plug in x = 7 into the equation and find the value [f(7) basically]
So, we have:
[tex]f(x)=1970.5x+10,002\\f((7))=1970.5(7)+10,002\\f(7)=23,795.5[/tex]
So, number of cars in 2016 : 23,795,500