Answer:
The required polynomial is [tex]x^4-3x^3-8x^2+12x+16[/tex]
Step-by-step explanation:
To find the polynomial when the zeros or the roots are given for example, [tex]a_1, a_2, ....a_n[/tex], then the polynomial will be given by [tex]\left(x-a_1\right)\left(x-a_2\right).......\left(x-a_n\right)[/tex].
So here also we will use this concept. Now the zeros of the polynomials is:
-2,-1,2,4, so these are the values of x here, and the polynomial is written as
[tex]\left(x+2\right)\left(x+1\right)\left(x-2\right)\left(x-4\right)[/tex]
Now, we will open the brackets to get the final polynomial expression, as follows:
[tex]\left(x+2\right)\left(x+1\right)\left(x-2\right)\left(x-4\right)\\=\left(x^2+3x+2\right)\left(x-2\right)\left(x-4\right)\\=\left(x^3+x^2-4x-4\right)\left(x-4\right)\\=x^4-3x^3-8x^2+12x+16[/tex]
So the required polynomial is formed.