Question

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Three runners Dave, Edith, and Foley all start at the same time for a 24 km race, and each of them runs at a constant speed. When Dave finishes the race, Edith is 8 km behind, and Foley is 12 km behind. When Edith finishes the race, how far behind is Foley, in km?

Answer 1

Answer:

4 Km behind.

Step-by-step explanation:

1. Draw a graph

2. make Dave Edith and Foley

3. 8-0 is 8 and 12-8 is 4

Answer 2

The speed is the distance covered by an object at a particular time. When Edith finishes the race, the distance by which Foley is behind is 6 km.

What is speed?

The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.

$\rm{Speed = \dfrac{Distance}{Time}$

Let the time in which Dave finishes the race be represented by t. Therefore, in time t Dave completed 24 km.

Given that When Dave finishes the race, Edith is 8 km behind. Therefore the distance that Edith will cover in time t is 16 km. Now, the speed of Edith will be,

Speed of Edith = 16 km /t

Also, When Dave finishes the race, Foley is 12 km behind. Therefore the distance that Edith will cover in time t is 12 km. Now, the speed of Edith will be,

Speed of Edith = 12 km /t

Now, the time it will take for Dave to finish the rest of 8 km distance is,

Time = 8 km / (16 km/t)

        = 0.5 t

Further, the distance that Edith will cover in time 0.5t is,

Distance = 0.5t × 12km/t

               = 6 km

Therefore, the distance that will be left for Foley is 6 km.

Hence, When Edith finishes the race, the distance by which Foley is behind is 6 km.

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