Question

Suppose a die is rolled twice and let P(A) = 1/2 P(B) = 1/3 find the requested probability

Answer 1

Answer:

Step-by-step explanation:

P(AUB)=P(A)+P(B)+P(A∧B),P(A∧B)=0 as both the events are independent.

P(AUB)=1/2+1/3=(3+2)/6=5/6

Answer 2

The probability value of P(A u B) is 2/3

How to determine the probability?

The probability values are given as:

P(A) = 1/2

P(B) = 1/3

The required probability is then calculated using:

P(A u B) = P(A) + P(B) - P(A) * P(B)

This gives

P(A u B) = 1/2 + 1/3 - 1/2 * 1/3

Evaluate the product

P(A u B) = 1/2 + 1/3 - 1/6

Take the LCM

P(A u B) = (3 + 2 - 1)/6

Evaluate

P(A u B) = 2/3

Hence, the probability value of P(A u B) is 2/3

Read more about probability at:

https://brainly.com/question/25870256

#SPJ9