Question

Calculate the centripetal force on the end of a 100 m (radius) massless cable that is rotating at 0.5 rev/s. Assume the mass on the end of the cable is 4 kg.

Answer 1

Answer:

$F_{cp}=3947.84N$

Explanation:

From the formula for centripetal force and acceleration we can deduce that:

$F_{cp}=ma_{cp}=m\frac{v^2}{r}=m\frac{(r\omega)^2}{r}=mr\omega^2=mr\omega^2$

Since one revolution is $2\pi\ rad$, 0.5 revolutions are $\pi\ rad$, so we have:

$F_{cp}=(4kg)(100m)(\pi\ rad/s)^2=3947.84N$