I need help to find the slope in this table. Ignore the writing please. THANK YOU SO MUCH.
![I need help to find the slope in this table Ignore the writing please THANK YOU SO MUCH class=](https://us-static.z-dn.net/files/da2/681aad4c94f5d2d0425e7a28f958aec7.jpg)
The slope value for the given table is 13.
Step-by-step explanation:
Step 1:
[tex]slope = \frac{y2-y1}{x2-x1}[/tex], where [tex]x1,y1[/tex] are the first set of values and [tex]x2,y2[/tex] are the second set of values.
The given table has three sets of values so we can calculate two values of the slope.
Step 2:
To calculate the first slope value, we use the first and second sets of values.
The values are [tex]x1=3,y1=39[/tex] and [tex]x2=5,y2=65[/tex].
The slope for the given values is;
[tex]slope = \frac{65-39}{5-3}[/tex] = [tex]\frac{26}{2}[/tex] = [tex]13.[/tex]
The slope for the first set of given values is 13.
Step 3:
To calculate the second slope value, we use the second and third sets of values.
The values are [tex]x1=5,y1=65[/tex] and [tex]x2=8,y2=104[/tex].
The slope for the given values is;
[tex]slope = \frac{104-65}{8-5}[/tex] = [tex]\frac{39}{3}[/tex] = [tex]13.[/tex]
The slope for the second set of given values is 13.
So the slope for the given set of values is 13.