Question

Determine the center and radius of the following circle equation:

22 + y2 – 10x + 18y + 42 = 0

Answer 1

Answer:

C(5,-9) and r=8.

Step-by-step explanation:

C(p, q) - center

r=radius

k:x^2 +y^2 +dx+ey+f=0

x^2+y^2 - 10x+18y+42=0

d=-10, e=18, f=42

p=-d/2=-(-10)/2=10/2=5

q=-e/2=-18/2=-9

r^2 =p^2+q^2-f

r^2 =5^2 +(-9)^2 - 42

r^2=25+81-42

r^2 =106-42

r^2 =64

r=sqrt(64)

r=8

C(p,q)=C(5,-9) r=8

Answer 2

Answer:

C(5,-9) and r=8.

Step-by-step explanation: