Question

An airplane needs to reach a velocity of 199.0 km/h to take off. On a 2000-m runway, what is the minimum acceleration necessary for the plane to take flight? Assume the plane begins at rest at one end of the runway.

Answer 1

Answer:

$0.76m/s^2$

Explanation:

We are given that

Final velocity, v=199 km/h=$199\times \frac{5}{18}=55.3m/s$

1km/h=$\frac{5}{18}m/s$

Initial velocity, u=0

S=2000 m

We know that

$v^2-u^2=2as$

Using the formula

$(55.3)^2=2a(2000)$

$a=\frac{(55.3)^2}{2\times 2000}$

$a=0.76m/s^2$

Hence, the minimum acceleration necessary for the plane to take flight=$0.76m/s^2$