Question

The elevator of a large building is to raise a net mass of 600 kg at a constant speed of 12 m/s using an electric motor. What is the minimum power rating of the motor?

Answer 1

Answer:

Explanation:

Given that.

Mass=600kg

v=12m/s

Since it is moving up then gravity is acting on it

take g=9.8m/s²

Then,

Power=workdone/time

Work done=force ×distance

Power=force×distance/time

Then, velocity =distance/time

So,

Power=force ×velocity.

The force to raise the object up is the weight of the object

Force=weight=mass ×gravity

Power=mass×gravity ×velocity.

Power=600×9.8×12

Power, =70560watts

Power=70.56KW

Answer 2

Explanation:

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