Respuesta :

Answer:

y + 1 = [tex]\frac{3}{4}[/tex](x - 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (5, 2)

m = [tex]\frac{2+1}{5-1}[/tex] = [tex]\frac{3}{4}[/tex]

Using (a, b) = (1, - 1), then

y - (- 1) = [tex]\frac{3}{4}[/tex](x - 1), that is

y + 1 = [tex]\frac{3}{4}[/tex](x - 1)

The slope of the line is 3/4

Step-by-step explanation:

The equation of a line passing through (x1, y1) and (x2, y2)

[tex]\frac{y-y1}{x-x1 }= \frac{y2-y1}{x2-x1} }[/tex]

From given point (1, -1) and (5, 2)

[tex]\frac{y-(-1)}{x-5} = \frac{2-(-1)}{5-1}[/tex]

or, [tex]\frac{y+1}{x-5} =\frac{3}{4}[/tex]

Hope it helps you

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