Answer:
Geometric
Step-by-step explanation:
[tex] \frac{8}{2} = 4 \\ \\ \frac{32}{8} = 4 \\ \\ \frac{128}{32} = 4 \\ \\ [/tex]
Here, common ratio (r = 4) is same, therefore given sequence is a geometric progression.
Recursive formula is given as:
[tex] t_n= ar^{n-1}\\\\
\therefore t_n= 2\times 4^{n-1}\\\\
\therefore t_n= 2\times 2 ^{2(n-1)}\\\\
\therefore t_n= 2\times 2 ^{2n-2}\\\\
\therefore t_n= 2 ^{2n-2+1}\\\\
\therefore t_n= 2 ^{2n-1}[/tex]
