Respuesta :

Answer and Step-by-step explanation:

[tex]Hello![/tex]

[tex]Let's~answer~this~question![/tex]

Answer for the first question :

→ [tex]We~have~that:[/tex]

[tex]x_{1}=3,[/tex]

[tex]y_{1}=2,[/tex]

[tex]x_{2}=2 ,[/tex]

[tex]y_{2}=0[/tex]

[tex]So,~d=\sqrt{(2-(3))^2+(0-(2))^2}=\sqrt{5}[/tex]

[tex]Thus, ~option~ "B"~ is~ correct![/tex]

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Answer for the second question :

→ [tex]The~midpoint~for~two~points~P=(x_{1}, y_{1})~and~Q=(x_{2}, y_{2}) ~is[/tex] [tex]M=(\frac{x_{1}~+~x_{2} }{2} ,\frac{y_{1}~+~y_{2} }{2})[/tex]

→ [tex]We~have~that:[/tex]

[tex]x_{1}=-1,[/tex]

[tex]y_{1}=0,[/tex]

[tex]x_{2}=1,[/tex]

[tex]y_{2}=2[/tex]

[tex]So, M=(\frac{(-1)+(1)}{2} ,\frac{(0)+(2)}{2})=(0,1).[/tex]

[tex]Thus,~option~"C"~is~correct![/tex]

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Answer for the third question :[tex]Just~like~the~previous~equation,~the~midpoint~for~two~points~P=(x_{1}, y_{1})[/tex]

[tex]and~Q=(x_{2}, y_{2}) ~is~M=(\frac{x_{1}~+~x_{2} }{2} ,\frac{y_{1}~+~y_{2} }{2})[/tex]

→ [tex]We~have~that:[/tex]

[tex]x_{1}=7,[/tex]

[tex]y_{1} =4,[/tex]

[tex]x_{2}=9,[/tex]

[tex]y_{2}=-1[/tex]

[tex]So, M=(\frac{(7)+(9)}{2} ,\frac{(4)+(-1)}{2})=8,\frac{3}{2} ~or,~(8,1.5)[/tex]

[tex]Thus,~option~"D"~is~correct![/tex]

Answer:

2) option 2

3) option 3

4) option 4

Step-by-step explanation:

2) sqrt[(3-2)² + (2-0)²]

= sqrt(1+4)

= sqrt(5)

3) Mp = (x1+x2)/2, (y1+y2)/2

= (-1+1)/2 , (0+2)/2

4) (7+9)/2, (4-1)/2

16/2 , 3/2

(8, 3/2)

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