have to finish before I sleeeep

Answer and Step-by-step explanation:
[tex]Hello![/tex]
[tex]Let's~answer~this~question![/tex]
Answer for the first question :
→ [tex]We~have~that:[/tex]
[tex]x_{1}=3,[/tex]
[tex]y_{1}=2,[/tex]
[tex]x_{2}=2 ,[/tex]
[tex]y_{2}=0[/tex]
[tex]So,~d=\sqrt{(2-(3))^2+(0-(2))^2}=\sqrt{5}[/tex]
[tex]Thus, ~option~ "B"~ is~ correct![/tex]
_________________________________________________
Answer for the second question :
→ [tex]The~midpoint~for~two~points~P=(x_{1}, y_{1})~and~Q=(x_{2}, y_{2}) ~is[/tex] [tex]M=(\frac{x_{1}~+~x_{2} }{2} ,\frac{y_{1}~+~y_{2} }{2})[/tex]
→ [tex]We~have~that:[/tex]
[tex]x_{1}=-1,[/tex]
[tex]y_{1}=0,[/tex]
[tex]x_{2}=1,[/tex]
[tex]y_{2}=2[/tex]
[tex]So, M=(\frac{(-1)+(1)}{2} ,\frac{(0)+(2)}{2})=(0,1).[/tex]
[tex]Thus,~option~"C"~is~correct![/tex]
_________________________________________________
Answer for the third question :[tex]Just~like~the~previous~equation,~the~midpoint~for~two~points~P=(x_{1}, y_{1})[/tex]
[tex]and~Q=(x_{2}, y_{2}) ~is~M=(\frac{x_{1}~+~x_{2} }{2} ,\frac{y_{1}~+~y_{2} }{2})[/tex]
→ [tex]We~have~that:[/tex]
[tex]x_{1}=7,[/tex]
[tex]y_{1} =4,[/tex]
[tex]x_{2}=9,[/tex]
[tex]y_{2}=-1[/tex]
[tex]So, M=(\frac{(7)+(9)}{2} ,\frac{(4)+(-1)}{2})=8,\frac{3}{2} ~or,~(8,1.5)[/tex]
[tex]Thus,~option~"D"~is~correct![/tex]
Answer:
2) option 2
3) option 3
4) option 4
Step-by-step explanation:
2) sqrt[(3-2)² + (2-0)²]
= sqrt(1+4)
= sqrt(5)
3) Mp = (x1+x2)/2, (y1+y2)/2
= (-1+1)/2 , (0+2)/2
4) (7+9)/2, (4-1)/2
16/2 , 3/2
(8, 3/2)