The perimeter of a playing field for a certain sport is 300ft. The field is a rectangle, and the length is 48ft longer than the width. Find the dimensions

Respuesta :

Answer:

Width of the rectangular field =[tex]102 feet[/tex]

Step-by-step explanation:

Perimeter of the field= [tex]300feet[/tex]

Length of the field= [tex]48 feet[/tex]

Width=?

Perimeter of a rectangular field= [tex]2(Length+Width)[/tex]

                                            [tex]300= 2(48+Width)\\\\150=48+Width\\\\Width=150-48\\\\Width=102 feet[/tex]

The Width of the rectangular field is [tex]102 feet[/tex]

Answer: the length is 99 feet and the width is 51 feet.

Step-by-step explanation:

Let L represent the length of the playing field.

Let W represent the width of the playing field.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of a playing field for a certain sport is 300ft. This means that

2(L + W) = 300

Dividing through by 2, it becomes

L + W = 150 - - - - - - - - - - - --1

The field is a rectangle, and the length is 48ft longer than the width. This means that

L = W + 48

Substituting L = W + 48 into equation 1, it becomes

W + 48 + W = 150

2W + 48 = 150

2W = 150 - 48

2W = 102

W = 102/2

W = 51

L = W + 48 = 51 + 48

L = 99

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