Answer:
236.63 rad/s²
Explanation:
From simple harmonic motion,
a = ω²r ........................ Equation 1
Where a = centripetal acceleration, ω = angular velocity, r = radius of the circle/ length of the string.
Given: r = 1.5 m, ω = 2 rev/s = (2×2π) rad/s = 4π rad/s
Substitute into equation 1
a = (4π)²1.5
a = 16×1.5×π²
a = 24π²
Where the value of π = 3.14,
therefore,
a = 24(3.14)²
a = 236.63 rad/s²
Hence the centripetal acceleration = 236.63 rad/s²
