Answer:
[tex]k=173.33\ \frac{lb.in}{K}[/tex]
Explanation:
Given that
The equation of ideal gas
P V= k T
P=Pressure
V=Volume
T=Temperature
k=Constant
V= 400 in³
P= 130 lb/in²
T= 300 K
Now by putting the values in the above equation
130 x 400 = k x 300
[tex]k=\dfrac{130\times 400}{300}\ \frac{lb.in}{K}[/tex]
[tex]k=173.33\ \frac{lb.in}{K}[/tex]
Therefor the value of k will be
[tex]k=173.33\ \frac{lb.in}{K}[/tex]