Question

Aqueous potassium phosphate reacts with aqueous aluminum chloride to form aqueous potassium chloride and solid aluminum phosphate. Write the balanced chemical equation for the reaction. Include physical states.

Answer 1

Answer:

Al^3+(aq) + PO4^3-(aq) → AlPO4(s)

Explanation:

Step 1: Data given

potassium phosphate = K3PO4

aluminum chloride = AlCl3

potassium chloride = KCl

aluminum phosphate = AlPO4

Step 2: The unbalanced equation

K3PO4(aq) + AlCl3(aq) → KCl (aq)+ AlPO4(s)

On the left side we have 3x K (in K3PO4), on the right side we have 1x K (in KCl). To balance the amount of K on both sides, we have to multiply KCl (on the right side ) by 3. Now the equation is balanced.

K3PO4(aq) + AlCl3(aq) → 3KCl(aq)+ AlPO4(s)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Al^3+(aq) + PO4^3-(aq) → AlPO4(s)

Answer 2

The balanced equation of the reaction between aqueous aluminum chloride and potassium phosphate to form aqueous potassium chloride and solid aluminum phosphate would be:

                   

$K_3PO_4(aq)$ +  $AlCl_3 (aq)$ --->  $3KCl (aq)$ +  $AlPO_4 (s)$

Aqueous potassium phosphate has the formula $K_3PO_4(aq)$

Aqueous aluminum chloride has the formula $AlCl_3 (aq)$

Aqueous potassium chloride has the formula $KCl (aq)$

Solid aluminum phosphate has the formula $AlPO_4 (s)$

The balanced equation for the reaction can, thus, be written as:

  $K_3PO_4(aq)$ +  $AlCl_3 (aq)$ --->  $3KCl (aq)$ +  $AlPO_4 (s)$

More on balancing chemical equations can be found here: https://brainly.com/question/20492533