Question

How do you solve the system 5x-3y=16 and 3x-5y=-4?

Answer 1

5x-3y=16

3x-5y=-4

Multiply the first equation by 3; the second one by 5

15x-9y=48

15x-25y=-20

Eq 1 - Eq 2:

-9y+25y=48+20=68

16y=68

4y=17

y=17/4

5x-3y=16

5x-3×17/4=16

5x=16+51/4=(64+51)/4=115/4

x=115/4/5=23/4

x=23/4