Question

find the sum of the first 3 terms of a geometric sequence with a=96 and r=1/4 the sum is____.

Answer 1

For Geometric sequence, the next term is multiplied by the common ratio.

Common ratio, r = 1/4

1st term, a = 96

2nd term = ar = 96*1/4 = 24

3rd term = ar² = 96*(1/4)*(1/4) = 6

Sum of the first three terms =    96 + 24 + 6 = 126