Question

Indicate the order of reaction consistent with each observation.
a. The half-life of the reaction gets shorter as the initial concentration is incr eased.
b. A plot of the natural Jog of the concentration of the reactant versus time yields a straight line.
c. The half-life of the reaction gets longer as the initial concentration is in creased.

Answer 1

Answer:

a. Second order

b. First order

c. zero order

Explanation:

a. For a second order reaction,

$t_{1/2}=\frac{1}{k[A_0]}$

As half life is inversely proportional to initial concentration, therefore, increase in intital concentration will decrease half life of the reaction.

b. First order reaction,

for first order reaction:

$k=\frac{1}{t} ln\frac{[A_0]}{[A]}$

$kt=ln[A_0]-ln[A]\\ln[A]=ln[A_0]-kt$

y = C + mx

Therefore, plot between ln A and  t is a straight line.

c. For a zero order reaction,

$t_{1/2}=\frac{[A_0]}{2k}$

Half life is proportional to initial concentration, therefore, increase in initial concentration will increase half life of the reaction.

Answer 2

The order of reaction is as follows:

a. Second order

b. First order

c. zero order

ORDER OF A REACTION:

a. For a second order reaction,

$t_{1/2}=\frac{1}{[A_0]}$

As the half life is inversely proportional to initial concentration, therefore, increase in intital concentration will decrease half life of the reaction.

b. First order reaction,

$ln[A]=ln[A_0]-kt$

Therefore, plot between ln A and t is a straight line.

c. For a zero order reaction,

$t_{1/2}=\frac{[A_0]}{2k}$

Half life is proportional to initial concentration, therefore, increase in initial concentration will increase half life of the reaction.

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