Answer:
a) The volume of the system is 3.062 Liters.
b) Percentage error results from assuming ideal-gas behavior is 9.36%.
Explanation:
a)
Using ideal gas equation:
PV = nRT
where,
P = Pressure of gas = [tex]10 atm[/tex]
V = Volume of gas = ?
n = number of moles of gas = 1 mol
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas = 100°C = 100+273K=373 K
Putting values in above equation, we get:
[tex](10 atm)\times V=1 mol\times (0.0821L.atm/mol.K)\times 373 K[/tex]
[tex]V=\frac{1 mol\times (0.0821L.atm/mol.K)\times 373 K}{10 atm}[/tex]
V = 3.062 L
The volume of the system is 3.062 Liters.
b)
Volume of the container = V' = 2.8 L
System volume = V = 3.062 L
Percentage error of volume:
To calculate the percentage error, we use the equation:
[tex]\%\text{ error}=\frac{|\text{Experimental value - Accepted value}|}{\text{Accepted value}}\times 100[/tex]
[tex]=\frac{|3.062L-2.8 L|}{2.8 L}\times 100=9.36\%[/tex]
Percentage error results from assuming ideal-gas behavior is 9.36%.