Answer:
After finding the electric potential VP at point P = Q/Чπϵ₀L ㏑(1+[tex]\frac{L}{d}[/tex])
Explanation:
I believe it is a part C question.
The derivative of V and P will be directly proportional to the differential dq and the inverse of Чπϵ₀δ........
Please find detailed solution in the attached picture as i believe that is the answer to the part C question you are seeking for.