Answer:
(c) 118/V100 11.8
Step-by-step explanation:
We use the central limit theorem to solve this question.
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]
In this problem, we have that:
[tex]\sigma = 118, n = 100[/tex]
So
[tex]s = \frac{118}{\sqrt{100}} = 11.8[/tex]
So the correct answer is:
(c) 118/V100 11.8