Answer:
0.6977 mg/L will the concentration be one day later.
Explanation:
Using integrated rate law for first order kinetics as:
[tex][A_t]=[A_0]e^{-kt}[/tex]
Where,
[tex][A_t][/tex] is the concentration at time t
[tex][A_0][/tex] is the initial concentration = 1.00 mg/L
k is the rate constant = 0.360 d⁻¹
time = 1 day
So,
[tex][A_t]=1.00\times e^{-0.360\times 1}\ mg/L=0.6977\ mg/L[/tex]
0.6977 mg/L will the concentration be one day later.