Answer: 0.00825 moles of hydrogen are produced.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
For aluminium:
Given mass of aluminium = 0.150 g
Molar mass of aluminium = 27 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of aluminium}=\frac{0.150g}{27g/mol}=0.0055mol[/tex]
The chemical equation for the reaction of aluminium and NaOH follows:
[tex]2Al+2NaOH+6H_2O\rightarrow 2NaAl(OH)_4+3H_2[/tex]
As, given amount of NaOH is in plenty. So, it is considered as an excess reagent.
Thus, aluminium is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of aluminium produces = 3 moles of hydrogen
So, 0.0055 moles of aluminium will produce = [tex]\frac{3}{2}\times 0.0055=0.00825mol[/tex] moles of hydrogen