Question

A 0.45 Caliber bullet (m = 0.162 kg) leaving the muzzle of a gun at 860 m/s.
What is the momentum?
O
O
O
140 kg*m/s
140 kg
62 kg*m/s
387 kg*m/s

Answer 1

Answer:139.32m/s

Explanation:

Mass=0.162kg

Velocity=860m/s

Momentum=?

Momentum=mass x velocity

Momentum=0.162 x 860

Momentum=139.32m/s

Answer 2

The momentum of the caliber bullet leaving the muzzle of the gun is approximately 140kgm/s.

Hence, option (a) 140kgm/s is the correct answer.

Given the data in the question;

• Mass of bullet; $m = 0.162kg$

• Velocity of the bullet; $v = 860m/s$

Momentum; $p = \ ?$

Momentum

Momentum is simply the product of the mass of an object or particle and its velocity. It is expressed as;

$Momentum (p) = m * v$

Where m is the mass of an object and v is its velocity.

We substitute our given values into the above expression

$Momentum(p) = m * v\\\\Momentum(p) = 0.162kg * 860m/s\\\\Momentum(p) = 139.32kgm/s\\\\Momentum(p) = 140kgm/s$

The momentum of the caliber bullet leaving the muzzle of the gun is approximately 140kgm/s.

Hence, option (a) 140kgm/s is the correct answer.

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