Question

The runner reaches the first camera, at the 500 m mark, at 9:03:05 a.m. and the second camera, at the 600 m mark, at 9:03:25 a.m. What is her average speed over that time interval

Answer 1

Answer:

Explanation:

Distance travelled = 600 - 500 = 100 m

Time taken = 9:03:25 a.m.-  9:03 :05 a.m.

= 20 s

average speed = distance / time taken

= 100 / 20 m /s

= 5 m /s