There are 6 Republican, 5 Democrat, and 4 Independent candidates. How many different ways can a committee of 3 Republicans, 2 Democrats, and 1 Independent be selected?

Respuesta :

Answer:

800

Step-by-step explanation:

6C3 × 5C2 × 4C1

20 × 10 × 4 = 800

A committee of 3 Republicans, 2 Democrats, and 1 Independent can be selected in 9,600 different ways.

Given that there are 6 Republican, 5 Democrat, and 4 Independent candidates, to determine in how many different ways can a committee of 3 Republicans, 2 Democrats, and 1 Independent be selected, the following calculation must be performed:

  • (6x5x4) x (5x4) x 4 = X
  • 120 x 20 x 4 = X
  • 9,600 = X

Therefore, a committee of 3 Republicans, 2 Democrats, and 1 Independent can be selected in 9,600 different ways.

Learn more in https://brainly.com/question/3775851

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