Answer:
The amount of time needed for this heating to occur is 126.25 min
Explanation:
Given;
power required to heat the room = 2kW
volume of the room = 5 m X 5 m X 6 m = 150 m³
atmospheric pressure at sea level = 101 Kpa
Internal energy available in this room, E = PV
= 101 Kpa*150m³
= 15,150 Kpa.m³ = 15,150 KJ
P*t = E
where;
t is the time required to heat this room
1 kW = 3600 kJ/h
2 kW = 7200 kJ/h
[tex]t = \frac{E}{P} = \frac{15150 KJ}{7200\frac{KJ}{h}} =2.104 {hours} = 126.25 min[/tex]
Therefore, the amount of time needed for this heating to occur is 126.25 min