Answer:
[tex]\large \boxed{\text{0.003 25 mol$\cdot$L$^{-1}$s}^{-1}}[/tex]
Explanation:
A ⟶ Products
[tex]\begin{array}{rc}\textbf{t/s} & \textbf{[A]/mol$\cdot$L}^{\mathbf{-1}} \\0 & 0.52 \\20 & 0.43 \\40 & 0.35 \\60 & 0.29 \\80 & 0.24 \\100 & 0.20 \\\end{array}[/tex]
I plotted your blue curve and the orange line in the diagram below.
Calculate the instantaneous rate
The instantaneous rate of reaction is the negative slope of the orange line.
[tex]\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\ & = & \dfrac{\text{(0.35 - 0.48) mol/L}}{\text{(40 - 0) s}}\\\\& = & -\dfrac{\text{0.13 mol/L}}{\text{40 s}}\\\\& = & -\textbf{0.003 25 mol$\cdot$L$^{\mathbf{-1}}$s}^{\mathbf{-1}} \\\\\end{array}\\\text{The instantaneous rate of reaction is $\large \boxed{\textbf{0.003 25 mol$\cdot$L$^{\mathbf{-1}}$ s}^{\mathbf{-1}}}$}[/tex]
Instantaneous rate of reaction is the rate of reaction at certain point of time. The instantaneous rate for given reaction is at 40 second is -0.00325 mol/L/s.
Instantaneous rate of reaction:
This is the rate of reaction at certain point of time.
For given reaction instantaneous rate can be calculated as,
[tex]\bold {m = \dfrac {y2- y1}{x2-x1}}[/tex]
Where,
y- concentration
x - time
[tex]\bold {m = \dfrac {(0.35- 0.48)\ mol/L}{(40-0)\ s}}\\\\\bold {m = \dfrac {(0.13)\ mol/L}{(40)\ s}}\\\\\bold {m = -0.00325\ mol /L /s }[/tex]
Therefore, the instantaneous rate for given reaction is at 40 second is -0.00325 mol/L/s.
To know more about Instantaneous rate,
https://brainly.com/question/24787663
