Answer:
In 5.148 moles there [tex]3.10\times 10^{24} [/tex] molecules of [tex]C_2H_6OC_2H_6O[/tex].
Explanation:
[tex]N=n\times N_A[/tex]
Where:
N = Number of particles / atoms/ molecules
n = Number of moles
[tex]N_A=6.022\times 10^{23} mol^{-1}[/tex] = Avogadro's number
We have:
Number of molecules [tex]C_2H_6OC_2H_6O[/tex] = N = [tex]3.10\times 10^{24} [/tex]
Moles of [tex]C_2H_6OC_2H_6O[/tex] = n =?
[tex]n=\frac{N}{N_A}=\frac{3.10\times 10^{24}}{6.022\times 10^{23} mol^{-1}}[/tex]
n = 5.148 moles
In 5.148 moles there [tex]3.10\times 10^{24} [/tex] molecules of [tex]C_2H_6OC_2H_6O[/tex].