Answer:
Correlation coefficient ≈ 0.9445
This indicates that the weight of a student increases as the height of the student increases.
Step-by-step explanation:
The rest of the question is the following table
value of x (height) are 58, 59, 60, 62, 63, 64, 66, 68, 70
Value of y (weight) are: 122, 128, 126, 133, 145, 136, 144, 150, 151
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To calculate the correlation coefficient we will use the following form:
[tex]r = \frac{n(\sum xy)- (\sum x)(\sum y)}{\sqrt{n\sum x^2 - (\sum x)^2} \sqrt{n\sum y^2-(\sum y)^2} }[/tex]
So, n (the number of terms) = 9
∑x = 570, ∑y= 1236, ∑ x²= 36234, ∑ y²= 170694 and ∑xy=78617
So, the correlation coefficient =
[tex]r = \frac{9\times 78617- 570\times 1236}{\sqrt{9\times 36234-(570)^2}\sqrt{9\times 170694-(1236)^2}}\\[/tex]
∴ r = 0.9445
So, weight of a student increases as the height of the student increases.
