Question

A farmer is using a rope and pulley to lift a bucket of water from the bottom of a well. The farmer uses a force F1 = 54.5 N to pull the bucket of water upwards at a constant speed. The bucket, when empty, has a mass of mb = 1.1 kg.

Answer 1

Answer:

(a) Mass of the water in the bucket is $4.46\ kg$.

(b) The volume of water will be $4460\ cm^3$

Explanation:

The question is incomplete the complete question is given below.

A farmer is using a rope and pulley to lift a bucket of water from the bottom of a well. The farmer uses a force $F_1 = 54.5\ N$ to pull the bucket of water upwards at a constant speed. The bucket, when empty, has a mass of $(m_b)$ = 1.1 kg.

(a) Calculate the mass of the water in the bucket, $(m_w)$ in kg

(b) Calculate the volume of the water in the bucket, $V_w$ in $cm^3$. Use density of the water 1.00 g/

Given the farmer uses a force $F_1 = 54.5\ N$ to pull out the bucket.

Also, the mass of the bucket $(m_b)$ is $1.1\ kg$

The force due to mass of bucket $(m_b)$ and mass of water $(m_w)$ will balance the force used by farmer.

So,

$F_1=(m_b+m_w)g$

$54.5=(1.1+m_w)\times 9.81\\\frac{54.5}{9.81}=(1.1+m_w)\\5.56=(1.1+m_w)\\m_w=5.56-1.1\\m_w=4.46\ kg$

So, mass of the water in the bucket is 4.46 kg.

Now, let us work on next part.

Given density of the water $\rho_w=1\ g/cm^3$

$\rho_w=\frac{m_w}{V_w}\\V_w=\frac{m_w}{\rho_w}$

$m_w=4.46\ kg=4.46\times1000\ g=4460\ g$

$V_w=\frac{4460}{1}=4460\ cm^3$

So, the volume of water will be $4460\ cm^3$