Question

A heavy ball with mass 10 kg is hung from the ceiling of Stolkin Auditorium on a rope of length 4.5 m. It is pulled to one side and released, swinging like a pendulum; at its lowest point, it reaches a speed of 6 m/s. What is the tension in the rope at that point?

Answer 1

Explanation:

The given data is as follows.

        mass = 10 kg,     length = 4.5 m

       speed (v) = 6 m/s

Now, formula to calculate tension is as follows.

           T = $mg + \frac{mv^{2}}{r}$

Putting the given values into the above formula as follows.

                T = $mg + \frac{mv^{2}}{r}$   (here r = l)  

                   = $10 \times 9.8 + \frac{10 \times (6)^{2}}{4.5}$

                   = (98 + 80) N

                   = 178 N

Thus, we can conclude that tension in the rope at that point is 178 N.