Question

Anthracite is a type of coal that is composed of carbon with small amounts of hydrogen, oxygen, nitrogen, and sulfur. The formula for a sample of anthracite is C 240 H 90 O 4 NS . Calculate the amount of carbon in 40.0 kg of the sample.

Answer 1

Answer:

The amount of carbon is 37.40 kg.

Explanation:

Molecular weight of anthracite (C240H90O4NS) = (12×240) + (1×90) + (16×4) + 14 + 32 = 2,880 + 90 + 64 + 14 + 32 = 3,080 g/mol

Molecular weight of carbon in anthracite = 12×240 = 2,880 g/mol

Mass of sample of anthracite = 40 kg

Amount of carbon = 2,880/3,080 × 40 kg = 37.40 kg

Answer 2

The amount of carbon in 40 Kg of anthracite, C₂₄₀H₉₀O₄NS, is 37.4 Kg

• We'll begin by calculating the molar mass of anthracite, C₂₄₀H₉₀O₄NS. This can be obtained as follow:

Molar mass of C₂₄₀H₉₀O₄NS = (12×240) + (1×90) + (4×16) + 14 + 32

= 3080 g/mol

Divide by 1000 to express in Kg/mol

= 3080 / 1000 = 3.08 Kg/mol

Mass of Carbon in C₂₄₀H₉₀O₄NS = 12 × 240 = 2880 g

Divide by 1000 to express in kg

= 2880 / 1000 = 2.88 Kg

Thus, we can say that:

3.08 Kg of C₂₄₀H₉₀O₄NS contains 2.88 Kg of C

• With the above information, we can obtain mass of Carbon in 40 Kg of C₂₄₀H₉₀O₄NS. This can be obtained as follow:

3.08 Kg of C₂₄₀H₉₀O₄NS contains 2.88 Kg of C

Therefore,

40 Kg of C₂₄₀H₉₀O₄NS will contain = $\frac{40 * 2.88}{3.08}$ = 37.4 Kg of C

Thus, the amount of carbon in 40 Kg of anthracite, C₂₄₀H₉₀O₄NS, is 37.4 Kg

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