Question

The formation of nitrogen dioxide and oxygen,

NO(g) + O3(g) ⇌ NO2(g) + O2(g)

is first order in NO and first order in O3. If the concentration of NO was increased by half and the concentration of O3 was quadrupled, by what factor would the reaction rate increase?

Answer 1

Answer:

The rate of reaction changes by a factor 6.

Explanation:

Given the reaction is first order.

Let us assume the initial concentration of $NO$ is $A$ and the initial concentration of $O_3$ is $B$.

So, we can write the rate of the reaction as

$R=k[A][B]$

Where,

$R$ is the rate of reaction. And $k$ is the rate constant.

Also, the initial concentration of $NO$ has been increased by $0.5$, and the initial concentration of  $O_3$ was increased by factor $4$.

So, we have

$R'=k[1.5A][4B]\\R'=6k[A][B]\\R'=6R$

We can see the rate of reaction changes by a factor 6.