Question

An electron traveling through a wire in an electric circuit experiences a constant force of 4 multiply 10-19 N, always in the direction of its motion. How much work is done on the electron by this force as it travels through 0.8 m of the wire?

Answer 1

Answer:

The work done on the electron by this force is $3.2\times10^{-19}\ J$

Explanation:

Given that,

Force $F=4\times10^{-19}\ N$

distance = 0.8 m

We need to calculate the work done on the electron by this force

Using formula of work done

$W=F\times d$

Where, F = force

d = distance

Put the value into the formula

$W=4\times10^{-19}\times0.8$

$W=3.2\times10^{-19}\ J$

Hence, The work done on the electron by this force is $3.2\times10^{-19}\ J$