PLZ HELP...Enter in standard form the equation of the line passing through the given point and having the given slope.
B(2,-5),m= -2/3

Standard form for the equation of the line is
[tex]$y=-\frac{2}{3} x-\frac{25}{3}[/tex]
Solution:
Given point is (2, –5).
slope of the line m = [tex]-\frac{2}{3}[/tex]
Here, [tex]x_1=2, y_1=-5[/tex]
Equation of a line passing through the point:
[tex]y-y_1=m(x-x_1)[/tex]
[tex]$y-(-5)=-\frac{2}{3} (x-(-5))[/tex]
[tex]$y+5=-\frac{2}{3} (x+5)[/tex]
[tex]$y+5=-\frac{2}{3} x-\frac{10}{3}[/tex]
Subtract 15 from both sides of the equation.
[tex]$y+5-5=-\frac{2}{3} x-\frac{10}{3}-5[/tex]
[tex]$y=-\frac{2}{3} x-\frac{25}{3}[/tex]
Standard form for the equation of the line is
[tex]$y=-\frac{2}{3} x-\frac{25}{3}[/tex]