Answer:
a) [tex]1.94 \frac{rad}{s}[/tex]
b) [tex]9.12\frac{m}{s}[/tex]
c) Towards the center of the centrifuge
Explanation:
a)
Becuse the centrifuge rotates in circular motion, there's an angular acceleration tha simulates high gravity accelerations
[tex]a_{rad}=\omega r^{2} [/tex]
with r the radius and ω the amgular velocity, in or case [tex] a_rad=3.5g[/tex] so:
[tex]3.5g=\omega r^{2} [/tex] and g=9.8[tex] \frac{m}{s^{2}}[/tex]
solving for ω:
[tex] \omega=\frac{3.5g}{r^2}=\frac{3.5*9.8}{4.2^2}[/tex]
[tex] \omega = 1.94 \frac{rad}{s}[/tex]
b) Linear speed (v) and angular speed are related by:
[tex]v=\omega r =(1.94)(4.7) [/tex]
[tex] v= 9.12\frac{m}{s}[/tex]
c) The apparent weigth is pointing towards the center of the circle, becuse angular acceleration is pointing in that direction.