Question

Consider the following network: proxy-cache On average there are 35 objects downloaded per second, and the average object size is 50,000 bits. What is the traffic intensity on the 2 Mbps access link?

a. 0.035
b. 0.007
c. 0.250
d. 0.875

Answer 1

Answer:

(d) 0.875 erlangs

Explanation:

In a digital network, the traffic intensity = $\dfrac {aL}{R}$

where

a = average arrival rate of packets = 35 objects downloaded per second

L is the average packet length = 50,000 bits (e.g. in bits), and

R is the transmission rate = 2 Mbps = 2,000,000 bits per second

Traffic Intensity = $\dfrac {aL}{R}=\dfrac {50000 X 35}{2000000}=\dfrac {1700000}{2000000}=0.875$