Answer:
E(Y') = ∅/(∅+1), also E(Y) = ∅/(∅+1)
Here sample mean is Y' and population mean is ∅/(∅+1). This means that Y' is a consistent estimator of ∅/(∅+1)
Step-by-step explanation:
I assume your question is:
A consistent estimator g Let Y₁, Y₂, Y₃....Υₙ be IID random variable where each random variable has PDF f(y) = ∅y^(∅ -1) for 0<y<1, and f(y) = 0 for all other values of y
Sample mean, Y is a consistent estimator of ∅/(∅+1) in the attached solution.