Question

If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI
10.4 moles NaCI
2.6 moles NaCI
5.2 moles NaCI
2 moles NaCI

Answer 1

Answer:

5.2moles of NaCl

Explanation:

The equation for the reaction is:

2Na + Cl2 —> 2NaCl

From the equation,

2moles of Na produced 2moles of NaCl.

Therefore, 5.2moles of Na will also produce 5.2moles of NaCl