Answer:
b. 2
Step-by-step explanation:
[tex]3^{2X}[/tex] = [tex]9^{3X - 4}[/tex] ------------------------------------(1)
To solve the equation above, we will follow the steps below;
9 = 3²
Will replace 9 = 3² in equation (1)
[tex]3^{2X}[/tex] = [tex](3^{2}) ^{3X - 4}[/tex]
open the bracket
[tex]3^{2X}[/tex] = [tex]3^{6x - 8}[/tex]
The 3 on the left-hand side will cancel-out the 3 on the right-hand side of the equation. Thus our equation becomes;
2x = 6x - 8
subtract 6x from both-side of the equation
2x - 6x = -8
-4x = -8
Divide both-side of the equation by -4
[tex]\frac{-4X}{-4}[/tex] = [tex]\frac{-8}{-4}[/tex]
(On the left-hand side of the equation, -4 will cancel-out -4 while on the right-hand side of the equation -8 will be divided by -4)
x = 2
