Answer:
The probability that a student reads exactly 2 of these 3 languages is 0.054.
Step-by-step explanation:
Denote the languages as follows:
F = French, G = German and S = Spanish.
The information provided is:
[tex]n(F)=72\\n(G)=40\\n(S)=39\\n(F\cap G)=18\\n(F\cap S)=18\\n(G\cap S)=9\\n(F\cap G\cap S)=6[/tex]
Compute the number of students who study only French and German as follows:
[tex]n_{only}(F\cap G)=n(F\cap G)-(F\cap G\cap S)=18-6=12[/tex]
Compute the number of students who study only French and Spanish as follows:
[tex]n_{only}(F\cap S)=n(F\cap S)-(F\cap G\cap S)=18-6=12[/tex]
Compute the number of students who study only German and Spanish as follows:
[tex]n_{only}(G\cap S)=n(G\cap S)-(F\cap G\cap S)=9-6=3[/tex]
Compute the number of students who reads exactly 2 of these 3 languages as follows:
[tex]n(2\ out\ of\ 3)=n_{only}(F\cap G)+n_{only}(F\cap S)+n_{only}(G\cap S)\\=12+12+3\\=27[/tex]
Thus, there are 27 students who reads exactly 2 of these 3 languages.
Compute the probability that a student reads exactly 2 of these 3 languages as follows:
[tex]P(2\ out\ of\ 3)=\frac{27}{500}= 0.054[/tex]
Thus, the probability that a student reads exactly 2 of these 3 languages is 0.054.