Question

2.
A diameter of a circle has endpoints
(7,0) and (7. -4). What is the equation
of the circle

Answer 1

The answer is (x-7)^2+(y+2)^2=(4)^2 or 16

Answer 2

Step-by-step explanation:

Equation of a circle in diameter form is given as:

$(x - x_1)(x - x_2) + (y - y_1)(y - y_2) = 0 \\ \\ \therefore \: (x - 7)(x - 7) + (y - 0)(y + 4) = 0\\ \\ \therefore \: (x - 7)^{2} +y(y + 4) = 0 \\ \\ \therefore \: {x}^{2} - 14x + 49 + {y}^{2} + 4y = 0 \\ \\ \purple{ \boxed{\therefore \: {x}^{2} + {y}^{2} - 14x + 4y + 49 = 0}} \\ is \: the \: required \: equation \: of \: the \: \\ circle$