what is the value of the discriminant, b2 āˆ’ 4ac, for the quadratic equation 0 = x2 āˆ’ 4x 5, and what does it mean about the number of real solutions the equation has?

Respuesta :

d = b^2 - 4ac, where a = 1, b = -4, c = 5
d = (-4)^2 - 4 x 1 x 5
d = 16 - 20
d = -4
Since d is negative, this means that there is no real solution to the equation.
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