Respuesta :
Answer:
a) NaHCO3 = 0.504 M
b) H2SO4 = 1.325 M
c) NaCl = 0.610 M
Explanation:
Step 1: Data given
Moles = mass / molar mass
Molarity = moles / volume
a. 19.5 g NaHCO3 in 460.0 ml solution
Step 1: Data given
Mass NaHCO3 = 19.5 grams
Volume = 460.0 mL = 0.460 L
Molar mass NaHCO3 = 84.0 g/mol
Step 2: Calculate moles NaHCO3
Moles NaHCO3 = 19.5 grams / 84.0 g/mol
Moles NaHCO3 = 0.232 moles
Step 3: Calculate molarity
Molarity = 0.232 moles / 0.460 L
Molarity = 0.504 M
b. 26.0 g H2SO4 in 200.0 mL solution
Step 1: Data given
Mass H2SO4 = 26.0 grams
Volume = 200.0 mL = 0.200 L
Molar mass H2SO4 = 98.08 g/mol
Step 2: Calculate moles H2SO4
Moles H2SO4 = 26.0 grams / 98.08 g/mol
Moles H2SO4 = 0.265 moles
Step 3: Calculate molarity
Molarity = 0.265 moles / 0.200 L
Molarity =1.325 M
c. 15.0 g NaCl dissolved to make 420.0 mL solution
Step 1: Data given
Mass NaCl = 15.0 grams
Volume = 420.0 mL = 0.420 L
Molar mass NaCl = 58.44 g/mol
Step 2: Calculate moles NaCl
Moles NaCl = 15.0 grams / 58.44 g/mol
Moles NaCl = 0.256 moles
Step 3: Calculate molarity
Molarity = 0.256 moles / 0.420 L
Molarity =0.610 M
